Question

Two resistor of resistance ratio 3:4 are connected in parallel. compare the magnitude of heat produced in them.

Answer 1

Two resistors of resistance ratio 3 : 4

Let proportionality constant is R

then, resistance of first resistor, $R_1$ = 3R

and resistance of 2nd resistor, $R_2$ = 4R.

both given resistors are connected in parallel. but we know, in parallel resistance, across each resistor appears same potential difference.

so, use formula of heat, $\mathbf{H=\frac{v^2}{r}t}$

v denotes potential difference across resistor , r denotes resistance and t time taken .

here, v and t are constant terms

so, Heat is inversely proportional to resistance.

hence, ratio of heat produced = $\frac{R_2}{R_1}$

= 4R/3R = 4/3

Answer 2

answer.4:3

here H=v^2×t/r so H is inversly proportional to r Resista

nce.where v potential and t time is constant.

now, given r1=3 and r2 is equal to 4

we know that from above H is inversly proportional of r.

H=1/r1/r2

H=1/3/4

H=1×4/3

H=4/3

H=4:3