Question

Two resistors 2Ω and 3 Ω are connected in series. How much heat will be generated across the combination if 2 A current flows through them for 10 s.

Answer 1

Explanation:

ANSWER

Energy dissipated = PtorVI×tor =I

2

Rt Joules

Consider Ohm's law V=IR.

In this case the resistors are connected in series and hence, the total resistance is 4+2=6 ohms. In a series circuit, the current remains the same throughout the circuit and so we use the I

2

Rt Joules formula.

The total current in the circuit is calculated as I=V/R=6/6=1ampere.

Therefore, the power dissipated P across the 4 ohm resistor for 5 s

= 1

2

×4×5=20Joules

Hence, The heat dissipated by the 4 resistor in 5 s will be 20 J.