Two resistors 20 ohms and 40 ohms are connected in series across a battery of 10 v. find the current flowing in the circuit.
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Answer:
0.75A
Explanation: Resistance=Potential/Current
First resistance(R1)=V1/I1
20=10/I1
so,I1=1/2A
R2=V2/I2
40=10/I2
so,I2=1/4
In series,Total current(I)=I1+I2
=1/2+1/4
=3/4=0.75A
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