Two resistors 3 Ω and 4 Ω in series are connected across a battery of emf and internal resistance 6 , 0.5 Ω. Find (a) the total current, and (b) the potential difference across each resistor.
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Answer:
a. 6/7.5= 0.8
b. across 3 ohm is 2.4
and across 4 is 3.2
Explanation:
1st we have to calculate yhe current across the whole circuit that should total voltage devided by total resistance.
then to potential difference across any of the resistor multiply resistance and current across circuit.
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