Question

Two resistors 3 ohm and 2 ohm are connected in parallel to a cell of emf 1.5 volt and internal resistance 0.3 ohm.Calculate the current drawn from the cel

Answer 1

Answer:

two resistors 10 ohm, 20 ohm and 30 ohm are. connected in series combination. i] Find equivalent resistance of series. combination.

Explanation:

correct answer

Answer 2

Answer:

The current drawn from the cell is 1A.

Explanation:

On the assumption that all physical parameters and temperatures remain constant, Ohm's law asserts that the voltage across a conductor is directly proportional to the current flowing through it.

V = IR

where,

V = voltage (V)

I = current (A)

R = resistance (ohm)

Given,

Resistance, R1 = 3 ohm

Resistance, R2 = 2 ohm

Emf, E = 1.5 V

Internal Resistance, r = 0.3 ohm

As the two resistance are connected in parallel. So,

Req = R1R2/(R1 + R2)

Req = 3×2/(3 + 2)

Req = 6/5 = 1.2 ohm

Using, Ohm's law

I = V/(Req + r)

I = 1.5/(1.2 + 0.3)

I = 1.5/1.5 = 1 A

Hence, the current drawn from the cell is 1A.

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