Question

Two resistors 3 ohm and 6 ohm are connected in parallel to a cell of emf 1.5v and internal resistance 1 ohm find the current through each resistors and also the current in the cir uit

Answer 1

R1 = 3 ohm
R2 = 6 ohm
R3 = 1 ohm
V   =  1.5 V

V = I1 * R1
1.5 = I1 * 3
1.5/3 = I1
1/2 = I1

V = I2 * R2
1.5 = I2 * 6
1.5/6 = I2
1/4

V = I3 * R3
1.5 = I3 * 1
1.5/1 = I3
0.66 = I3

I = I1 + I2 + I3
I = 1/2 + 1/4 + 0.66
I = 1.41

Answer 2

Concept

• The rate of electron passage in a conductor is known as electric current. The SI Unit of electric current is the Ampere.
• Resistance is a characteristic of a conductor whereby it opposes the flow of electric current through it. It is determined by the relationship between the applied voltage and the electric current that passes through it.

Given

Resistors given are 3 ohm , 6 ohm and 1 ohm connected in parallel to cell

Voltage given is 1.5v

Find

We need to find the current in each resistors and current in the circuit

Solution

Given that

$R_1= 3$ Ω

$R_2= 6$ Ω

$R_3 = 1$ Ω

Now We know that V = I*R

For $R_1$

$V = I_1 *R_1$

$1.5= I_1 *3$

∴ $I_1= 0.5 A$

The current through the Resistor (R1) is 0.5A

Now for $R_2$

$V = I_2*R_2$

$1.5= I_2*6$

∴$I_2=0.25 A$

The current through the Resistor (R2) = 0.25A

Now for $R_3$

$V = I_3*R_3\\1.5 = I_3 * 1$

∴ $I_3 = 1.5$

The current in third resistor R3 = 1.5 A

Now to calculate the total current in the circuit

$I = I_1+I_2+I_3\\I = 0.5 +0.25 +1.5\\I = 2.25A$

Total current in the circuit is 2.25A

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