Question

Two resistors 4 Ohm and 6 Ohm are connected in parallel. The combination is connected across a
6 V battery of negligible resistance. Calculate (i) the current through the battery (ii) current through each resistor.​

Answer 1

the current through the battery is 0.4ohm

Answer 2

Answer:

the current through the battery is : 2.5A (2) current through each resistor is 1.5 A and 1.0 A

Explanation:

v=6v

Rp =1/R1 + 1/R2 =1/4+1/6

Rp = 6+4/24 =10/24

Rp=24/10=2.4 ohm

acc. to ohm's law

V=I.R

I=V/R

I=6/2.4

I=2.5 A

(2) a. V=6V, R=6 ohm , I=?

I=V/R

I=6/6

I=1

(b.) V=6V,R=4ohm ,I =?

I=V/R

I=6/4

I=1.5A