Question

two resistors 40 ohm and 80 ohm are connected in parallel across a potential difference of 200 volt how much current is flowing in the circuit​

Answer 1

Answer:

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Explanation:

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Answer 2

$\huge\sf\pink{Answer}$

☞ Current through the circuit is 7.5 A

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$\huge\sf\blue{Given}$

✭ Two resistors of 40Ω & 80Ω are connected in parallel

✭ Potential difference is 200 V

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$\huge\sf\gray{To \:Find}$

◈ The current in the circuit?

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$\huge\sf\purple{Steps}$

We know that resistance of a parallel connection is given by,

$\underline{\boxed{\sf \dfrac{1}{R_{net}} = \dfrac{1}{R_1} + \dfrac{1}{R_2}.....+\dfrac{1}{R_n}}}$

Substituting the given values,

➝ $\sf \dfrac{1}{R_{net}} = \dfrac{1}{R_1} + \dfrac{1}{R_2}.....+\dfrac{1}{R_n}$

➝ $\sf \dfrac{1}{R_{net}} = \dfrac{1}{40} + \dfrac{1}{80}$

➝ $\sf \dfrac{1}{R_{net}} = \dfrac{2}{80} + \dfrac{1}{80}$

➝ $\sf \dfrac{1}{R_{net}} = \dfrac{3}{80}$

➝ $\sf \red{R_{net} = \dfrac{80}{3}}$

So now the current in the circuit can be found with the help of the Ohm's law,

$\underline{\boxed{\sf V = IR}}$

Substituting the values,

➳ $\sf V = IR$

➳ $\sf 200 = I \times \dfrac{80}{3}$

➳ $\sf 200\times \dfrac{3}{80} = I$

➳ $\sf \orange{I = 7.5 \ A}$

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