Physics, asked by noratejesvi, 1 year ago

Two resistors 400 ohm and 800 ohm are connected in series with a 6 V battery. What will be the reading in the ammeter of 10 ohm resistance?

RishabhRDX: Mark brainliest plz

Answers

Answered by SubhasishBhaduri

10

As we know, V = IR

So,
I = V/R
I = 6/1210. [ since- 800 ohm + 400 ohm + 10 ohm = 1210 ohm ]
I = 0.00496 A
I = 4.96 mA

RishabhRDX: use that ammeter 's resistance also

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