Question

Two resistors 400 ohm and 800 ohm are connected in series with a 6 V battery. What will be the reading in the ammeter of 10 ohm resistance?

Answer 1

As we know, V = IR

So,
I = V/R
I = 6/1210. [ since- 800 ohm + 400 ohm + 10 ohm = 1210 ohm ]
I = 0.00496 A
I = 4.96 mA