Two resistors, A and B, are connected in series to a 6.0-V battery. A voltmeter is connected across the resistor. measures a voltage of 4.0 V. When the two resistors are connected in parallel across the 6.0-V battery, the current through B is found to be 2.0 A. Find the resistances of A and B
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When the resistors are in series the voltage drop across B is 6V - 4V = 2V
When the resistors are in parallel the voltage is the same across both A and B. Therefore you have the current andthe voltage across B and can us Ohm's Law to find the resistance.
R=VI=6 V2.0 A=3.0 ohm
Now jumping back to the series circuit you now have the resistance of B you can find the current using Ohm's Law
I=VR=2 V3 Ohm=0.667 A
and since current is the same in for all resistances in a series circuit this is the same current through A And B.
A=VI=4V0.667A=6?
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