Physics, asked by jayasreeanand21, 6 months ago

Two resistors are connected in parallel across a 24 V supply and a current of 3A flows in

the circuit. If one of the resistors has a resistance of 2 ῼ, determine the value of the other

resistor.​

Answers

Answered by Ekaro
11

Correct Question :

Two resistors are connected in parallel across a 24 V supply and a current of 3A flows in the circuit. If one of the resistors has a resistance of 12Ω determine the value of the other resistor.

Given :

Two resistors are connected across a battery of 24V.

Current flow = 3A

One of the two resistors has a resistance of 2Ω.

To Find :

Resistance of other resistor.

Solution :

★ As per ohm's law, current flow in circuit is directly proportional to the applied potential difference at constant temperature. [V = I × R]

➠ V = I × R

➠ 24 = 3 × R

➠ R = 24/3

R = 8Ω

Hence equivalent resistance of the parallel connection is 8Ω.

Equivalent resistance of parallel :

  • 1/R = 1/R₁ + 1/R₂

By substituting the values,

⭆ 1/8 = 1/12 + 1/R₂

⭆ 1/R₂ = 1/8 - 1/12

⭆ 1/R₂ = (3 - 2) / 24

⭆ 1/R₂ = 1/24

R₂ = 24Ω

Answered by Lovelyfriend
5

Correct Question :

Two resistors are connected in parallel across a 24 V supply and a current of 3A flows in the circuit. If one of the resistors has a resistance of 12Ω determine the value of the other resistor.

Given :

Two resistors are connected across a battery of 24V.

Current flow = 3A

One of the two resistors has a resistance of 2Ω.

To Find :

Resistance of other resistor.

Solution :

★ As per ohm's law, current flow in circuit is directly proportional to the applied potential difference at constant temperature.. [V = I × R]

➠ V = I × R

➠ 24 = 3 × R

➠ R = 24/3

➠ R = 8Ω

Hence equivalent resistance of the parallel connection is 8Ω.

Equivalent resistance of parallel :

1/R = 1/R₁ + 1/R₂

By substituting the values,

⭆ 1/8 = 1/12 + 1/R₂

⭆ 1/R₂ = 1/8 - 1/12

⭆ 1/R₂ = (3 - 2) / 24

⭆ 1/R₂ = 1/24

⭆ R₂ = 24Ω

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