two resistors are connected in series and then in parallel. What effect will it have on the readings of voltmeter and ammeter?
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when we connect two resistant in series
r1 + r2= r
in parallel
1/r1 + 1/r2 = 2/r
therefore
r (parallel) = 1/2 r(series)
r1 + r2= r
in parallel
1/r1 + 1/r2 = 2/r
therefore
r (parallel) = 1/2 r(series)
rjrahul5523:
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