Question

two resistors are connected in series give an equivalent resistance of 10 ohm and if connected in parallel give 24 ohm​

Answer 1

Answer:

Given RS=10Ω;RP=2.4Ω;R1=?;R2=?

Solution:

Effective resistance when connected in series and parallel.

RS=R1+R2=10  

RP1=R11+R21=R1R2R1+R2

∴RP=R1+R2R1R2=2.4

From egn (1) and (2)

10R1R2=2.4

⇒R