Two resistors are connected in series with 5V battery of negligible internal resistance.
A current of 2A flows through each resistor. If they are connected in parallel with the
same battery a current of flows through combination. Calculate the value of each
resistance.
Answers
Answered by
6
Answer:
V=IR
R=V/i
R=5/2
R=2.5
. V=ir so on interchange we will get
R=V/I
Similar questions