Two resistors are connected in series with 5V battery of negligible internal resistance.
A current of 2A flows through each resistor. If they are connected in parallel with the
same battery a current of flows through combination. Calculate the value of each
resistance.
Answers
Answered by
1
Answer:
If resistors are connected in series there would be flow of less current
V=IR
R=V÷I
=5÷2
=2.5
Rs = 1.25+1.25
If it is connected in parralel, then
The current flow would be increase because there won't be more restrict of flow of current
1/Rp = 1/1.25+1/1.25
=2.5/1.5625
Rp=1.6/2.5
=1.28
1.3
Similar questions