Question

two resistors connected in parallel across 200 v supply take 10 A from the mains if the power dissipated in one resistor is 800 w. find the value of the other resistor ​

Answer 1

Answer:

answer is 100

Explanation:

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Answer 2

Answer:

33.33ohms

Explanation:

Gvn:

   R1 and R2 is in parallel.

   I=10A

   As parallel circuit, V = V1 = V2 = 200V

   P1=800W

Formulas:

   P=VI

   P=(V*V)/R

Solution:

   Total power in circuit,

               P(total)=V*I=200*10

                           =2000W

   P2=P(total)-P1=2000-800

        =1200W

   P2=(V*V)/R2 ====> R2=(V*V)/P2

                                        =(200*200)/1200

                                    R2=33.33ohms