Two resistors each of 10 Ω are connected in i) series ii) and then in parallel to a battery of 6 V. Calculate the ratio of power consumed in the combination of resistor in two case.
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Step-by-step explanation:
When the two resistors are in series, total resistance
= Rs=10+10=20Ω
Is=V/R=6/20=0.3A
When the two resistors are connected in parallel, total resistance :
1/Rp=1/10+1/10
⇒Rp=5Ω
Ip=6/5=1.2A
Power = V I
Thus, the ratio of power consumed in series and parallel combination is;
Ps/Pp=0.3/1.2=0.25
Answered by
1
Step-by-step explanation:
Two resistors each of 10 Ω are connected in i) series ii) and then in parallel to a battery of 6 V. Calculate the ratio of power consumed in the combination of resistor in two case.
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