Math, asked by deependradeepa, 2 months ago

Two resistors each of 10 Ω are connected in i) series ii) and then in parallel to a battery of 6 V. Calculate the ratio of power consumed in the combination of resistor in two case.​

Answers

Answered by nareshpatle1915
1

Step-by-step explanation:

When the two resistors are in series, total resistance

= Rs=10+10=20Ω

Is=V/R=6/20=0.3A

When the two resistors are connected in parallel, total resistance :

1/Rp=1/10+1/10

⇒Rp=5Ω

Ip=6/5=1.2A

Power = V I

Thus, the ratio of power consumed in series and parallel combination is;

Ps/Pp=0.3/1.2=0.25

Answered by saniyapatle45
1

Step-by-step explanation:

Two resistors each of 10 Ω are connected in i) series ii) and then in parallel to a battery of 6 V. Calculate the ratio of power consumed in the combination of resistor in two case.

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