Question

two resistors each of value R firstly connected in series and then parallel find ratio of net resistance in series to the net resistance in parallel​

Answer 1

Answer:

First in series

R(total)=r1+r2+....r(n)

Here r1=r2=r(n)

So net resistance=nr

In parallel

1/R(total)=1/r1 + 1/r2 + 1/r(n)

r1=r2=r(n)

So 1/R= n/r

R(parallel)=r/n

First in series

R(total)=r1+r2+....r(n)

Here r1=r2=r(n)

So net resistance=nr

In parallel

1/R(total)=1/r1 + 1/r2 + 1/r(n)

r1=r2=r(n)

So 1/R= n/r

R(parallel)=r/n

So ratio of series / parallel= nr / (r/n)

= n raised to power 2 or ( n square

So ratio of series / parallel= nr / (r/n)

= n raised to power 2 or ( n square

Explanation: