Question

two resistors have resistance 6Ω and 12Ω are connected first in series and then in parallel which combination have. higher resistance. How many times higher?

THE CORRECT AND DETAILED ANSWER WILL BE MARKED AS BRAINLIEST...!!​

Answer 1

Answer:

Series and 4.5

Explanation:

Given:

• Resistance of the first resistor = 6Ω
• Resistance of the second resistor = 12Ω

To find:

• Where higher resistance is found and how many times higher

series:

when two resistors are connected in series,Req =R1+R2

Req = 6+12

Req = 18Ω

Parallel:

when two resistors are connected in parallel,

1/Req = 1/R1 + 1/R2

1/Req = 1/R1 + 1/R2

1/Req = 1/6 + 1/12

1/Req = 2/12 + 1/12

1/Req = 3/12

Req = 12/3

Req = 4Ω

The resistance in the series is higher by 4.5 times