Question

Two resistors have resistance
8 ohm and 6 ohm are connected
in series across cell. what
is equivant resistance​

Answer 1

Answer:

• 14 ohms is the required equivalent resistance.

Explanation:

GIVEN:-

• Resistance of Resistor ,R1 = 8 Ω
• Resistance of 2nd Resistor ,R2 = 6 Ω

TO FIND:-

• Equivalent Resistance ,Req

SOLUTION:-

As we know that equivalent resistance in series is calculated by the sum of Resistance of each individual Resistors.

• Req = R1 + R2 + ..

Substitute the value we get

➾ Req = 8 Ω + 6 Ω

➾ Req = 14 Ω

• Hence, the equivalent resistance of the resistors is 14 ohms.

Answer 2

Answer:

Given :-

• Two resistors have resistance 8 ohm and 6 ohm are connected in series accross cell.

To Find :-

• What is the equivalent resistance.

Formula Used :-

$\clubsuit$ Equivalent Resistance in series :

$\longmapsto \sf\boxed{\bold{\pink{R_{eq} =\: R_1 + R_2 . . . . R_n}}}$

where,

• $\sf R_{eq}$ = Equivalent Resistance
• $\sf R_1$ = Resistance of resistors R₁
• $\sf R_2$ = Resistance of resistors R₂

Solution :-

Given :

• R₁ = 8 ohm
• R₂ = 6 ohm

According to the question by using the formula we get,

$\implies \sf R_{eq} =\: 8\: \Omega + 6\: \Omega$

$\implies \sf R_{eq} =\: (8 + 6)\Omega$

$\implies \sf\bold{\red{R_{eq} =\: 14\: \Omega}}$

$\therefore$ The equivalent resistance of resistors is 14 Ω .

$\rule{150}{2}$

$\bigstar$ Extra Information :

$\clubsuit$ Equivalent Resistance in parallel :

$\longmapsto \sf\boxed{\bold{\pink{\dfrac{1}{R_{eq}} =\: \dfrac{1}{R_1} + \dfrac{1}{R_2} + . . . . \dfrac{1}{R_n}}}}$