Physics, asked by saisatvik2212, 9 months ago

Two resistors having a resistance 4ohm and 6ohm are connected in a parallel. Find efficient resistance

Answers

Answered by sathish24499k

0

Answer:

Rp=(r1r2)/(r1+r2)=(4*6)/(4+6)=24/10=2.4ohm

Explanation:

Answered by kumarkapil2864

1

r1= 4 ohm

r2= 6 ohm connected in parallel

1/rp= 1/4+1/6

= 3+2/12

= 5/12

rp/1 = 12/5= 2.4 ohm

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