two resistors having equal resistance when connected in series have equivalent resistance of 48 ohm calculate the equivalent resistance when both are joined in parallel combination
Answers
Answered by
3
if two resistors are equal and they are connected in series so
current in one resistor = 24 ohm
if they are joined in parallel
than
total resistance
1/R = 1/24+1/24
1/R = 2/24
R= 12 ohm
current in one resistor = 24 ohm
if they are joined in parallel
than
total resistance
1/R = 1/24+1/24
1/R = 2/24
R= 12 ohm
Pradnya786:
okkk Text you copy will automatically show here
Answered by
3
Question :-
Two resistors having equal resistance when connected in series have equivalent resistance of 48 ohm calculate the equivalent resistance when both are joined in parallel combination.
_____________________________________________
Answer :-
Whenever R₁ and R₂ are in parallel ,
1 / RE = 1 / R₁ + 1 / R₂ [ RE = equivalent resistance ]
Let the two resistances be R.
According to the problem :
1 / 48 = 1 / R + 1 / R
==> 1 / 48 = ( 1 + 1 ) / R
==> 1 / 48 = 2 / R
Cross multiply to get :
==> R = 48 × 2
==> R = 96
The resistances are 96 Ω each
Hope it helps !
_________________________________________________________
Similar questions