Question

Two resistors having resistances of 16 Ω and 14Ω are connected in series.If a potential difference of 18 V is applied across them, calculate the current flowing through the circuit and the potential difference across each individual resistor.​

Answer 1

ANSWER

Given:

A resistance of 16Ω is connected in series with another resistance of 14Ω. A potential difference of 18V is applied across the combination.

To find:

The current through the circuit

Solution:

As, the resistance are connected in series

so, R = R1+R2

R =16 + 14 = 30Ω

Now according to Ohm's law,

v = I R

⟹ I= R/V

⟹ I = 30/ 18

⟹ I = 1.66A

So, 1.66A of current flow through circuit.