Two resistors of 1 ohm each are connected across 3 volt battery in series. Calculate the power delivered by each resistor and the total power delivered.
Answers
Answer:
Resistance, R
A
=4Ω
Resistance,R
B
=6Ω
Voltage,V=6V
i) As resistance are connected in parallel
Equivalent resistance =
R
1
=
R
A
1
+
R
B
1
2
1
=
4
1
+
6
1
=
24
10
R=2.4Ω
As power,P=
R
V
2
=
2.4
(6)
2
=15w
ii) Power dissipation across each resistor, p=VI
Current acorss resistor R
A
.I
A
=
R
A
V
I
A
=
4
6
=1.5A
Power dissipation across resistor R
A
P=VI
A
=6×1.5=9w
iii) Current across resistor R
B
.I
B
=
R
B
V
I
B
=
6
6
=1A
Power dissipation accross resistor R
B
P=VI
B
=6×1=6w
Explanation:
Resistance, R
A
=4Ω
Resistance,R
B
=6Ω
Voltage,V=6V
i) As resistance are connected in parallel
Equivalent resistance =
R
1
=
R
A
1
+
R
B
1
2
1
=
4
1
+
6
1
=
24
10
R=2.4Ω
As power,P=
R
V
2
=
2.4
(6)
2
=15w
ii) Power dissipation across each resistor, p=VI
Current acorss resistor R
A
.I
A
=
R
A
V
I
A
=
4
6
=1.5A
Power dissipation across resistor R
A
P=VI
A
=6×1.5=9w
iii) Current across resistor R
B
.I
B
=
R
B
V
I
B
=
6
6
=1A
Power dissipation accross resistor R
B
P=VI
B
=6×1=6w
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