Question

Two resistors of 10 10 ohms and 15 ohm are connected in a series to a battery of 6 volt how can the value of current pass through them

Answer 1

Resistance ($R_1$) = 10 Ω

Resistance ($R_2$) = 15 Ω

Total resistance = 10 + 15 = 25 Ω

Potential difference = 4 Volts

Let the current passing through them I.

According to ohm's law, V = IR

$I = \frac{V}{R}$

$I= \frac{6}{25}$

Current (I) = 0.24 A

Hence, the current passing through them is 0.24 A