Two resistors of 10 Ω and 15 Ω are connected in series to a battery of 6 V. Find the value
of current in circuit.
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Answer:
Resistance of the two resistors are
10Ω and 15Ω
They are connected in series,
R=R1+R2
R=25Ω
V=6v
From the ohms law,
V=iR
i= 6/25A
Explanation:
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