two resistors of 10 ohm and 15 ohm are connected in parallel combination circuit with 3 volt battery find the total resistance and the current flowing through each resistor
Answers
Answered by
23
This is very simple.
total resistance=6ohm
current in circuit=0.5A
current in 10ohm=0.3A
current in 15ohm=0.2A
total resistance=6ohm
current in circuit=0.5A
current in 10ohm=0.3A
current in 15ohm=0.2A
pubg70:
you have to solve this properly
not only write the answer
this is a doubt clearong platform not for cutting legs
if u jave the question regarding combinations formula i can help
see total caculate total resistanve of parallel combinations
the formula is 1/r =1/r1 +1/r2
and using ohms law u can calculate other values
hope u satisfied
i dont have the habit of solving by beautifully edited solutions. I do solve but most with explanation. because more than the numerical is important to understand the related concept
yup
Answered by
26
Hey buddy,
◆ Answer-
I1 = 0.3 A
I2 = 0.2 A
R = 6 ohm
◆ Explaination-
# Given-
R1 = 10 ohm
R2 = 15 ohm
V = 3 V
# Solution-
Let I1 & I2 be the currents flowing through each resistor.
As resistors are connected in parallel, same amount of voltage will be applied to both.
Thus,
I1 = V/R1 = 3/10 = 0.3 A
I2 = V/R2 = 3/15 = 0.2 A
Equivalent resistance for parallel combination is -
1/R = 1/R1 + 1/R2
1/R = 1/10 + 1/15
R = 10×15 / (10+15)
R = 6 ohm
Hope it helps...
◆ Answer-
I1 = 0.3 A
I2 = 0.2 A
R = 6 ohm
◆ Explaination-
# Given-
R1 = 10 ohm
R2 = 15 ohm
V = 3 V
# Solution-
Let I1 & I2 be the currents flowing through each resistor.
As resistors are connected in parallel, same amount of voltage will be applied to both.
Thus,
I1 = V/R1 = 3/10 = 0.3 A
I2 = V/R2 = 3/15 = 0.2 A
Equivalent resistance for parallel combination is -
1/R = 1/R1 + 1/R2
1/R = 1/10 + 1/15
R = 10×15 / (10+15)
R = 6 ohm
Hope it helps...
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