Question

Two resistors of 10 ohm and 15 ohm are connected to a battery of 12v. Calculate A. Minimum current flowing through circuit. B. Maximum current flowing through circuit C. Draw electric circuit for both(a) and(b) also calculate net resistance

Answer 1

Resistor 1= R1= 10ohm

Resistor 2= R2=15ohm

Potential Difference= 12v

A) Minimum Current flowing through the circuit
when the two resistors are connected in series

Rs= R1+R2
Rs= 10+15
Rs= 25ohm

Current (I)= V/Rs
=12/25
=0.48A

B) Maximum current flows through the circuit when it is connected in parallel

Rp= R1×R2/R1+R2
Rp= 150/25
Rp= 6ohm

Current (I)=V/Rp
=12/6
=2A

Answer 2

Answer:

Explanation:

From the ohms law

I=V/R

I=12/10

I=1.2Amp

Provided:

No other element or no other source connected in the circuit.

If any other source or element connected use Kvl and calculate the voltage across the resistor 10 ohm. Then calculate current flowing in resistor by applying I=V/R.