Question

Two resistors of 10 ohm and 20 ohm and an ideal inductor of 10H are connected to a 2v battery. The key is shorted at time t=0. Find the initial and final currents through the battery.

Answer 1

The value of initial current I = 1 /15 A and value of final current I2 = 1 / 10 A

Explanation:

10Ω  and 20Ω resistance are in series combination.

Net resistance = (10+20) =30Ω

Now

Initial Current "I" =  2 / 30 = 1 / 15 A

Similarly at infinity;

t→∞ current attains a mximum value.

Now

Final Current "I2" = 2 /20 = 1 /10 A

Thus the value of initial current I = 1 /15 A and value of final current I2 = 1 / 10 A.