Two resistors of 10 ohm and 20 ohm are joined in parallel . A potential difference of 12 v is applied across the combination. Find the power consumed by each resistor?
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Two resistors of resistance 10 Ohm and 20 Ohm are joined in series. A potential difference of Bara (12) Volt is applied across the combination. What is the power consumed by each resistor?
The resistancece of the combination of two resistors of 10 Ohm and 20 Ohm connected in series = 30 Ohm
Potential difference across the combination = 12 V
Current in the series circuit = 12/ 30 amp. = 2/5 amp = 0.4 amp
i² =0.4² amp² = 0.16 amp²
Power consumed in the 10 Ohm resistor = i²×10 = 0.16 amp² × 10 Ohm = 1.6 watt
Power consumed in the 12 Ohm resistor = i² × 20 Ohm= 0.16 amp²×20 = 3.2 watt.
The resistancece of the combination of two resistors of 10 Ohm and 20 Ohm connected in series = 30 Ohm
Potential difference across the combination = 12 V
Current in the series circuit = 12/ 30 amp. = 2/5 amp = 0.4 amp
i² =0.4² amp² = 0.16 amp²
Power consumed in the 10 Ohm resistor = i²×10 = 0.16 amp² × 10 Ohm = 1.6 watt
Power consumed in the 12 Ohm resistor = i² × 20 Ohm= 0.16 amp²×20 = 3.2 watt.
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Answer:
4.8 watts
Explanation:
Given that 2 resistors of 10 ohm and 20 ohm are connected in series.
Total resistance (R) = R₁+R₂ = 10+20 = 30Ω
Potential difference (V) = 12v
Power consumed (P) = ?
From ohms law, V = iR
i = V/R ----- 1
We know that, P = iV
From 1,
P = V²/R
Placing the given values in the formula P = 12 x 12 / 30
. P = 4.8 w
Therefore, Power consumed = 4.8 watts .
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