two resistors of 10 ohm and 5 ohm are connected in parallel Eight such sets are connected in series.find the equivalent resistance of this combination.
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given,
r1=10 ohm
r2= 5ohm
therfore total resistance in one set1/R =1/r1 +1/r2 = 1/10+1/5 =3/10 that is R=10/3
now resistance in 8 sets connected inseries =8*10/3=80/3=26.67 ohmm
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r1=10 ohm
r2= 5ohm
therfore total resistance in one set1/R =1/r1 +1/r2 = 1/10+1/5 =3/10 that is R=10/3
now resistance in 8 sets connected inseries =8*10/3=80/3=26.67 ohmm
Hope it helps you plzzz mark me as brainly
sarithprasadpb8ojr:
nice answer
thanks
why multiple with 10/3 with8
10/3 in one set so 8*10/3 in 8 set
thanks
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