two resistors of 10 ohms and 15 ohms are connected in series to a battery of 6 v . how can the value of the current passing through them be compared?
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Answered by
3
FIRST WE FIND TOTAL RESISTANCE
IN SERIES, TOTAL R=R₁+R₂.........RN
HERE, TOTAL RESISTANCE=10Ω+15Ω=25Ω
ALSO WE KNOW THAT Δ V=IR (ΔV IS POTENTIAL DIFFERENCE)
HERE I=?
R=25Ω
Δ V=6 volts
PUTTING IN THE EQUATION
6=I×25
I=6/25À
IN SERIES, TOTAL R=R₁+R₂.........RN
HERE, TOTAL RESISTANCE=10Ω+15Ω=25Ω
ALSO WE KNOW THAT Δ V=IR (ΔV IS POTENTIAL DIFFERENCE)
HERE I=?
R=25Ω
Δ V=6 volts
PUTTING IN THE EQUATION
6=I×25
I=6/25À
ET10400:
I am sorry ...i have got one doubt ....but in question it is asked about "how can the values of current passing through them compared?" so my doubt is ..that. i have understood what u have done..but i still don't get the comparing part...#Kshitijmanitiwari
Answered by
2
In a series connection
total resistance is equal to R=r1+r2+r3+r4+...............+rinfinity
total resistance offred by object =10Ω+15Ω=25Ω
Change in potential diffrenece=IR
6=I×25
so I=6/25
total resistance is equal to R=r1+r2+r3+r4+...............+rinfinity
total resistance offred by object =10Ω+15Ω=25Ω
Change in potential diffrenece=IR
6=I×25
so I=6/25
I am sorry ...i have got one doubt ....but in question it is asked about "how can the values of current passing through them compared?" so my doubt is ..that. i have understood what u have done..but i still don't get the comparing part...#Rajusetu
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