Question

Two resistors of 12 Ohms each are first connected in series and then connected in parallel. Find (1) Total resistance in both cases. (2) Total current if connected to a battery of 6 volt for both cases. ​

Answer 1

Explanation:

(1)

Series:

R=R1+R2=12+12=24 ohm

Parallel:

1/R=1/R1+1/R2=1/12+1/12=2/12=1/6

R=6 ohm

(2)

Series:

V=6 volt

V=IR

I=V/R=6/24=1/4=0.25 A

Parallel:

I=V/R=6/6=1 A

Answer 2

Explanation:

Explanation: (1) Series: R=R1+R2=12+12324 ohm

Parallel: 1/R=1/R1+1/R2=1/12+1/12%3D2/12=1/6 R=6 ohm

(2) Series: V=6 volt V=IR |=V/R=6/24=1/43D0.25 A

Parallel: I=V/R=6/6%3D1 A