Question

two resistors of 12ohm and 12ohm are connected in parallel.what is the resistance of the combination

Answer 1

Hey Friend,

When Resistors are connected in parallel, the overall resistance is decreased. The total resistance in a parallel circuit is always less than any of the individual resistances in parallel.

R1 = 12 ohm
R2 = 12 ohm

Formula - 
1/R = 1/R1 + 1/R2
1/R = 1/12 +1/12
1/R = 1/6
R = 6 ohm

Therefore, the resistance of the combination is 6 ohm.

Hope it helps!

Answer 2

When resistances are connected in parallel then the overall resistance is decreased as compared to the individual resistances.

Formula used -->

1/R(eq) = 1/R1 + 1/R2

Here,
R(eq) = Equivalent resistance
R1 =First Resistance = 12 ohm
R2 = Second Resistance = 12 ohm

1/R(eq) = 1/12 + 1/12

1/R(eq) = 2/12

1/R(eq) = 1/6

R(eq) = 6 ohm.