Question

Two resistors of 15 ohm and 10 ohm are connected in parallel this combination is connected in series with 24 hour and 15 volt battery find the current through 10 ohm resistor

Answer 1

1/Req=1/R1+1/R2

Req=R1R2/R1+R2

Req=150/25

=6 ohm

V=IR

15=I 6

I=15/6=5/2 amp

Let us assume that the current flowing through the 10 ohm resistor is I'

Then the current flowing through it is

I'=IR2/R1+R2

I=5/2

R1=15, R2=10

Then I'=1/2=0.5 amp