Question

two resistors of 15 ohm and Rohm are connected in parallel and if their effective resistance is 6 ohm find the value of R​

Answer 1

Answer:

here is ur required answer

Answer 2

Answer:

In a parallel connection Effective Resistance

=( I/R1) +(1/R2)

effective resistance = 6ohms

so, (1/15) + (1/R2) =1/ 6

= R2+15/15R2=1/6

= 15R2=6R2+90

=9R2=90

=R2=10ohms

Verification

1/Reff=(1/15)+ (1/10)

1/Reff= 5/30

Reff= 6ohms.....

HOPE THE ANSWER IS CLEAR.......