Question

two resistors of 1k ohm and 200 ohm are connected in series with a 12V battery calculated the current flowing in the circuit and the voltage developed across the 200 ohm resistor?​

Answer 1

Answer:

The answers is in the attached photo:

Explanation:

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Answer 2

Explanation:

1kohm=1000ohm

total resistance=1000+200

=1200ohm

V=12

So,

I=V/R

I=12/1200

I=1/100

I=0.01A

V across the 200 ohm resistance

=>V=IR

=>V=0.01×200

=>V=1/100×200

=>V=1×2

=>V=2