Question

Two resistors of 2 Ω and 4 Ω are connected in series to a battery of 18 V. Find

(a) Total resistance of circuit

(b) Total current flow in circuit

(c) Current flow in 2Ω resistors

(d) Potential difference across 4 Ω resistors​

Answer 1

Answer:

(a) 6  Ω (b) 3A (c) 3 A (d) 12 V

Explanation:

(a) R series = R1+R2 = 2+4 = 6 Ω

(b) V = IR, I = V/R = 18/6 = 3A

(c) In series combination the current is constant throughout the circuit, therefore, I =3A even in this case.

(d) V= IR = 3 * 4 = 12V

Answer 2

Answer:

a. 6 ohm

b. 18/6 = 3 amp

c. 3 amp

d. 4 x 3 = 12 V