Question

.Two resistors of 3 ohm and 6 Ohm , and a 6 volt battery are given.

(a)Find out the effective resistance, when these resistors are connected

in series​

Answer 1

Given:

Two resistors of 3 ohm and 6 Ohm , and a 6 volt battery are given.

To find:

• Net resistance
• Net current through circuit

Calculation:

Net resistance will be algebraic addition of the individual resistance because the resistors are connected in series.

$R = R1 + R2$

$\implies \: R = 3 + 6$

$\implies \: R = 9 \: ohm$

Now, current through circuit :

$i = \dfrac{V}{R}$

$\implies i = \dfrac{6}{9}$

$\implies i \approx 0.67 \: amperes$

So, net resistance is 9 ohm and current through circuit is 0.67 Ampere.