Two resistors of 3 ohm and 6 ohm I n parallel are connected to cell of emf and resistance of 0.5 ohm calculate the current
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1 /equivalent resistance= 1/3 +1/6 as these resistance are connected in parallel.
so, 1/r=(2+1)/6
so, 1/r=1/2
so, r=2 ohm
but V=v assume
also cell resistance=0.5ohm
so, overall equivalent resistance=0.5+2=2.5ohm
as V=IR
so, I=v/2.5 Ampere
so, 1/r=(2+1)/6
so, 1/r=1/2
so, r=2 ohm
but V=v assume
also cell resistance=0.5ohm
so, overall equivalent resistance=0.5+2=2.5ohm
as V=IR
so, I=v/2.5 Ampere
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