Two Resistors of 3 ohm each unknown resister are connected in a series across a 12 volt battery. If the potential difference across unknown resistor R is 6volt. Then, find :-
[1.] Potential Difference across 3 ohm resistor.
[2.] The current passing through unknown resistor R.
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HEYA MATE HERE IS YOUR ANSWER:
Solution:
R1=3 ohms
Second resistance=R2 ohms
As they are connected in series :
Eff R= R1+R2
=3+R2 ohms
V=12V
V2=6V
AS IT IS SERIES CONNECTION:
V=V1+V2
12= V1+6
V1= 6VOLTS
POTENTIAL DROP ACROSS FIRST RESISTANCE IS 6V
By ohms law:
V1=IR1
6=Ix3
I=6/2=3A
In series connection:
I=I1=I2
So current ACROSS unknown resistance is also 2A
V2=IR2
6=2xR2
R2=6/2=3ohms
Unknown resistance =3ohms
Effective resistance in Series = 3+3=6ohms
MARK AS BRAINIEST IF FOUND HELPFULL.
Solution:
R1=3 ohms
Second resistance=R2 ohms
As they are connected in series :
Eff R= R1+R2
=3+R2 ohms
V=12V
V2=6V
AS IT IS SERIES CONNECTION:
V=V1+V2
12= V1+6
V1= 6VOLTS
POTENTIAL DROP ACROSS FIRST RESISTANCE IS 6V
By ohms law:
V1=IR1
6=Ix3
I=6/2=3A
In series connection:
I=I1=I2
So current ACROSS unknown resistance is also 2A
V2=IR2
6=2xR2
R2=6/2=3ohms
Unknown resistance =3ohms
Effective resistance in Series = 3+3=6ohms
MARK AS BRAINIEST IF FOUND HELPFULL.
gurukiran1234:
really helpful ur a genius
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