Question

two resistors of 4and6ohm are connected in parallel.Calculate the current flowing through each resistor if V=6V​

Answer 1

Answer:2.5ampere

Explanation:

Given

r1=4ohm

r2=6ohm

V=6v

I=?

Solution

since the connection is in parallel

it's then,

1/Rt=1/r1+1/r2

1/Rt=1/4+1/6

1/Rt=(3×1+2×1)/12

1/Rt=(3+2)/12

1/Rt=5/12

Rt=12/5ohm

But,

I=V/R

I=6v/(12/5)ohm

I=6v×5/12ohm

I=30/12amps

I=2.5amps

therefore the current passed is 2.5 ampere