Question

Two resistors of 4ohms and 6 ohms are connected in parallel. If the total current is 30A, find the current through each resistor. *​

Answer 1

Answer:

• Current through 4 ohm resistor is 18 A.
• Current through 6 ohm resistor is 12 A.

Explanation:

Given:-

• Resistance of Resistor ,R1 = 4 ohm
• Resistance of Resistor ,R2 = 6 ohm
• Current ,I = 30 A

To Find:-

• Current through each resistors

Solution:-

As we know that the Equivalent resistance in Parallel series is calculated by the sum of reciprocal of resistance of each individuals resistors.

• 1/Req = 1/R1 + 1/R2

Substitute the value we get

→ 1/Req = 1/4 + 1/6

→ 1/Req = 6+4/24

→ 1/Req = 10/24

→ Req = 24/10

→ Req = 2.4 ohms.

Now, Calculating the Potential Difference

Using Ohm's Law

• V = IR

where,

• V denote Potential Difference
• I denote Current
• R denote Resistance

Substitute the value we get

→ V = 30×2.4

→ V = 72 v

Potential difference through each Resistors is 75 Volts

Now, Calculating the Current through 4 ohm resistor

Using Ohm's Law

→ 72 = I' × 4

→ I' = 72/4A

→ I' = 18 A

• Hence, the current through 4 ohm resistor is 18 Ampere.

And, Current through 6 ohm resistor

→ 72 = I" × 6

→ I" = 72/6

→ I" = 12 A

• Hence, the current through 6 ohm resistor is 12 Ampere

Answer 2

$\huge \bf Given$

Two resistor of 4 Ω and 6 Ω are connected in parallel.

Current = 30 A

$\huge \bf To \: Find$

Current through one resistor

$\huge \bf Solution$

As we know that

1/Rⁿ = 1/R1 + 1/R2

1/R = 1/4 + 1/6

1/R = 6 + 4/24

1/R = 10/24

R = 2.4 Ohm

Now,

V = IR

V = 30 × 2.4

V = 72 V

Now,

72 = I × 4

72/4 = I

18 = I

Current = 18 Ampere

Now,

V = IR

72 = I × 6

72/6 = I

12 = I