two resistors of 6 and 3 are connected in parallel.four such combination in series. calculate the equivalent residents of the combination thus formed.
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3
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⭐Hey here is your answer ⭐
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According to question ....two resistor of 6V and 3V are connected in parallel......
R1 = 6V
R2 = 3V
According to Ohm's laws
1/R' = 1/R1 + 1/R2
= 1/6V + 1/3V
=(3 + 6)/6
= 9/6
3/2 Ω...,
Therefore total resistance of combination formed....3/2Ω
____________________________
____________________________
I HOPE IT WILL HELP YOU ☺️✌️
⭐Hey here is your answer ⭐
___________________________
___________________________
According to question ....two resistor of 6V and 3V are connected in parallel......
R1 = 6V
R2 = 3V
According to Ohm's laws
1/R' = 1/R1 + 1/R2
= 1/6V + 1/3V
=(3 + 6)/6
= 9/6
3/2 Ω...,
Therefore total resistance of combination formed....3/2Ω
____________________________
____________________________
I HOPE IT WILL HELP YOU ☺️✌️
Anonymous:
sry ....bro maine ek mistake ki h
Answered by
7
The total resistance is 4 Ohm
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