Question

Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power
consumed by the 6 Ω resistor is:
A. 384 W
B. 576 W
C. 1500 W
D. 1800 W

Answer 1

V = IR
P = I^2 * R

V = 120 V
R = 6 + 9 = 15 ohms

I in the circuit
= V/R
= 120/15
= 8 Amp.

Power consumed by 6 ohm resistor
= I^2 * R
= (8)^2 * 6
= 64 * 6
= 384 W

So the answer is option (A) 384 W