Two resistors of 6 ohm and 3 ohm are connected in series four such combination are connected in parallel calculate the equivalent resistance of the combination thus formed
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Answer:series equivalent of given two resistors is
R(equi)= 6+3= 9 Ohm.
Now, by question, four such combination is connected in parallel.
Therefore, parallel equivalent of such 4 combinations will be
R(equi)= 9*9*9*9÷[9+9+9+9]
=81*81÷36
= 182.25 ohm
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