Physics, asked by Chahalsaab1286, 1 year ago

Two resistors of 6 ohm and 3 ohm are connected in series four such combination are connected in parallel calculate the equivalent resistance of the combination thus formed

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Answered by Anonymous

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Answered by hancyamit2003

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Answer:series equivalent of given two resistors is

R(equi)= 6+3= 9 Ohm.

Now, by question, four such combination is connected in parallel.

Therefore, parallel equivalent of such 4 combinations will be

R(equi)= 9*9*9*9÷[9+9+9+9]

=81*81÷36

= 182.25 ohm

Explanation:

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