Two resistors of resistance 1.0 Ω and 2.0 Ω connected in parallel are linked in series to a 3.0 Ω resistor. All three of this is in parallel with a fourth resistor. If the total effective resistance is 1.0 Ω, what is the resistance of the fourth resistor?
A.11/3
B.11/8
C.4
D.3
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Answer:
11/8
Explanation:
1 and 2 in parallel so there effective resistance is 2/3
2/3 and 3 in series so effective resistance 11/3
11/3 and x in parallel there effective resistance is
11/3*x/(11/3+x) = 1
=> 11/3*x = 11/3+ x
=> 8/3x = 11/3 So x= 11/8
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