Physics, asked by priya676817, 9 months ago

two resistors of resistance 10 ohm and 15 ohm are connected in series to a 5V battery. calculate the current through the conductors and heat produced in 5 minutes​

Answers

Answered by neilakkiya
1

Explanation:

Resistor 1= R1= 10ohm

Resistor 2= R2=15ohm

Potential Difference= 12v

A) Minimum Current flowing through the circuit

when the two resistors are connected in series

Rs= R1+R2

Rs= 10+15

Rs= 25ohm

Current (I)= V/Rs

=12/25

=0.48A

B) Maximum current flows through the circuit when it is connected in parallel

Rp= R1×R2/R1+R2

Rp= 150/25

Rp= 6ohm

Current (I)=V/Rp

=12/6

=2A

Answered by Anurag612
0

Explanation:

Let R1 be 10 ohms and R2 be 15 ohms resistors,

Since R1 and R2 are connected in series

Therefore, total resistance (R) =R1 +R2= 10 +15=25ohms

Now

Current (I) = V/R = 5/25 =1/5 Amperes

Given, time (t) = 5 minutes = 300 seconds

Therefore

Heat produced =I^2Rt

= (1/5)^2 *25*300

=1/25*25*300

=300 Joules

Second method

Work done(W) = energy(E) or Heat, since heat is also a form of heat (work energy theorem)

W = V*Q(charge)

E= V*Q

= 5*It (Q=It)

= 5 * 1/5*300

=5*60

=300 joules

Similar questions