Question

two resistors of resistance 10 ohm and 15 ohm are connected in parallel to a 12 volt battery . calculate the heat generated in the circuit in 5 min.
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Answer 1

Answer:

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Explanation:

Let R1 be 10 ohms and R2 be 15 ohms

resistors,

Since R1 and R2 are connected in series

Therefore, total resistance (R) =R1+R2= 10 +15=25ohms

Now

Current (I) = V/R = 5/25 =1/5 Amperes Given, time (t) = 5 minutes = 300 seconds

Therefore

Heat produced =1^2Rt

= (1/5)^2 *25*300

=1/25*25*300

=300 Joules

Second method

Work done(W) = energy(E) or Heat, since heat is also a form of heat (work energy

theorem)

W = V*Q(charge)

E= V*Q

= 5*It (Q=It)

= 5 * 1/5*300

=5*60

= 300 joules

Answer 2

Answer:

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