two resistors of resistance 10 R and 20 R are connected in parallel. A battery supplies 6 A of current to the combination. Calculate the current in each resistor.
Answers
ANSWER :
Given :
▪ Two resistors of resistance 10Ω and 20Ω are connected in parallel.
▪ A battery supplies 6A of current to the combination.
To Find :
▪ Current flow in each resistor.
Concept :
✏ First we have to find out equivalent resistance of the given parallel combination.
✏ After that, we have to calculate potential difference across the parallel combination.
✏ After this two steps, we can calculate current flow in each resistor with the help of ohm's law.
✏ Formula of equivalent resistance for parallel combination is given by
☞ Req = R1R2/(R1+R2)
✏ As per ohm's law, relation b/w potential difference and current flow is given by
☞ V = IR
Calculation :
✒ Equivalent resistance of combination :
→ Req = R1R2/(R1+R2)
→ Req = 10×20/(10+20)
→ Req = 200/30
→ Req = 20/3Ω
✒ Potential difference across battery :
→ V = I(Req)
→ V = 6×20/3
→ V = 2×20
→ V = 40volt
✒ Current flow in 10Ω resistor :
→ V = (I1)(R1)
→ 40 = (I1)(10)
→ I1 = 40/10
→ I1 = 4A
✒ Current flow in 20Ω resistor :
→ V = (I2)(R2)
→ 40 = (I2)(20)
→ I2 = 40/20